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3/r^2-147=0
Domain of the equation: r^2!=0We multiply all the terms by the denominator
r^2!=0/
r^2!=√0
r!=0
r∈R
-147*r^2+3=0
We add all the numbers together, and all the variables
-147r^2+3=0
a = -147; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-147)·3
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*-147}=\frac{-42}{-294} =1/7 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*-147}=\frac{42}{-294} =-1/7 $
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